python中怎么打印文件的前几行，很多新手对此不是很清楚，为了帮助大家解决这个难题，下面小编将为大家详细讲解，有这方面需求的人可以来学习下，希望你能有所收获。
head.py
# -*- coding: UTF-8 -*-#!/usr/bin/python# by Jakcing 2019.02.17# print first n lines or last n lines in big file import sysimport getoptimport linecacheVERSION="1.1"def get_line_count(filename): line_count = 0 file = open(filename,'r+', encoding='utf-8') while True: buffer = file.read(8192 * 1024 ) if not buffer: break line_count += buffer.count('\n') file.close() return line_countdef read_head_line(flist, line_num): for file_name in flist: print("===%s===" % file_name) f = open(file_name, 'r', encoding='utf-8') if(f): for i in range(line_num): print(f.readline(), end='')def read_last_line(flist, line_num): for file_name in flist: linecache.clearcache() line_count = get_line_count(file_name) print('===%s=== line count total: %d' % (file_name, line_count)) line_count = line_count - line_num +1 print('===%s=== line %d to end' % (file_name, line_count)) for i in range(line_num): last_line = linecache.getline(file_name, line_count) #从第line_count行读起 print('line[%d]:%s' % (line_count, last_line), end='') line_count += 1try: opts, args = getopt.getopt(sys.argv[1:], "hvn:t:", ["help", "output=", "numline=", "tail=", "version"])except getopt.GetoptError: print("argv error,please input")for cmd, arg in opts: if cmd in ("-h", "--help"): print("usage: head.py -n number filename \nor head.py -t number filename") sys.exit() elif cmd in ("-n", "--numline"): #打印文件开头的line_num行 line_num=int(arg) file_names=args[:] read_head_line(file_names, line_num) elif cmd in ("-t", "--tail"): #打印文件结尾的line_num行 line_num=int(arg) file_names=args[:] read_last_line(file_names, line_num) elif cmd in ("-v", "--version"): print("%s %s" % (sys.argv[0], VERSION))sys.exit()看完上述内容是否对您有帮助呢？如果还想对相关知识有进一步的了解或阅读更多相关文章，请关注创新互联行业资讯频道，感谢您对创新互联网站建设公司，的支持。
