给你个例子希望可以帮到你
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递归系统目录结构.
递归整个C盘目录:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim iDir As IO.Directory
Dim node As New TreeNode
'先把C盘添加到树中
TreeView1.Nodes.Clear()
node.ImageIndex = 0
node.Text = "本地磁盘 C:"
node.SelectedImageIndex = -1
TreeView1.Nodes.Add(node)
Dim i As Integer
'获取C:盘根目录下的文件夹
Dim str() As String = IO.Directory.GetDirectories("D:\")
For i = 0 To str.GetUpperBound(0)
'调用遍历过程
AddDirectory("C:", str(i), node)
Next
node = Nothing
iDir = Nothing
End Sub
Public Sub AddDirectory(ByVal strFatherPath As String, ByVal strPath As String, ByVal nodeFather As TreeNode)
Dim iDir As IO.Directory
'Dim iDirInfo As IO.DirectoryInfo
Dim i As Integer
Dim node As New TreeNode
'先添加本目录，从文件夹路径分析出文件夹名称
node.Text = Strings.Replace(strPath, strFatherPath "\", "", , 1)
'为单个节点指定节点未被选中时显示的图标
node.ImageIndex = 1
'为单个节点指定节点被选中时显示的图标
node.SelectedImageIndex = 2
nodeFather.Nodes.Add(node)
Application.DoEvents()
Try
Dim str() As String = IO.Directory.GetDirectories(strPath)
'遍历该目录的子文件夹
For i = 0 To str.GetUpperBound(0)
AddDirectory(strPath, str(i), node)
Next
Catch ex As Exception
Debug.WriteLine(ex.Message)
End Try
node = Nothing
iDir = Nothing
End Sub
这种不要用递归,知道关键字长度,知道节数用判断就可以了,取前3位第一节,第二节取3个为父节点,取全部为第二节关键字,第三节取前6个为父节点,取全部为第三节关键字.
并没有要求培养字段，查询时从len(ID)=3*N，每次循环时N都+1
select * from tablename where len(id)=3
select case N
case 1
treeview.node.add id,name
case 2
treeview.node(left(id,3)).node.add id,name
case 3
treeview.node(left(id,3)).node(left(id,6)).add id,name
end select
查询结果排个升序就不会存在这样的问题了,你刚才说的那种,如果中间没有比001001001001001更短的关键字,那么就脱节,这种是不可能添加到treeview中.
递归一般用在不知道节数,没有关键字的情况,比如系统目录结构.
递归整个C盘目录:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim iDir As IO.Directory
Dim node As New TreeNode
'先把C盘添加到树中
TreeView1.Nodes.Clear()
node.ImageIndex = 0
node.Text = "本地磁盘 C:"
node.SelectedImageIndex = -1
TreeView1.Nodes.Add(node)
Dim i As Integer
'获取C:盘根目录下的文件夹
Dim str() As String = IO.Directory.GetDirectories("D:\")
For i = 0 To str.GetUpperBound(0)
'调用遍历过程
AddDirectory("C:", str(i), node)
Next
node = Nothing
iDir = Nothing
End Sub
Public Sub AddDirectory(ByVal strFatherPath As String, ByVal strPath As String, ByVal nodeFather As TreeNode)
Dim iDir As IO.Directory
'Dim iDirInfo As IO.DirectoryInfo
Dim i As Integer
Dim node As New TreeNode
'先添加本目录，从文件夹路径分析出文件夹名称
node.Text = Strings.Replace(strPath, strFatherPath "\", "", , 1)
'为单个节点指定节点未被选中时显示的图标
node.ImageIndex = 1
'为单个节点指定节点被选中时显示的图标
node.SelectedImageIndex = 2
nodeFather.Nodes.Add(node)
Application.DoEvents()
Try
Dim str() As String = IO.Directory.GetDirectories(strPath)
'遍历该目录的子文件夹
For i = 0 To str.GetUpperBound(0)
AddDirectory(strPath, str(i), node)
Next
Catch ex As Exception
Debug.WriteLine(ex.Message)
End Try
node = Nothing
iDir = Nothing
End Sub
首先VB是不推荐用递归算法的，效率太低，建议用循环做
然后你的dm是string，那么它咋就能作为二维数组的下标呢？
再说你的条件是 ri = TabA(i, 0) ，不是 ri=tab（i,dm）啊？
