t = "1234a789405450"
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tt = InStr(t, "a") - 1
If tt 1 Then
t = Mid(t, 1, tt)
MsgBox t
End If
Dim regex=New System.Text.RegularExpressions.Regex("\(([^\)]*)\)")
Dim s= regex.Replace("(111)k(222)","$1")
'定义一个find函数
Private Function find(s1 As String, s2 As String) As String
Dim i As Integer
For i = 1 To Len(s1)
If i = InStr(1, s1, s2, vbTextCompare) Then
find = Left(s1, i - 1) Right(s1, Len(s1) - Len(s2) - i + 1)
Exit Function
End If
Next i
find = s1
End Function
'将Text1.Text中的Text2.Text字符删除
Private Sub Command1_Click()
Dim s As String
s = find(Text1.Text, Text2.Text)
Text1.Text = s
End Sub
