小编给大家分享一下怎么用Java语言实现Base64编码，希望大家阅读完这篇文章之后都有所收获，下面让我们一起去探讨吧！
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import java.io.*;
public class MIMEBase64 {
/*
这是个简单的Base64编码程序
作者：Roc Chen rocanny@163.com
Base64 使用US-ASCII子集的65个字符, 每个字符用6位表示
因此"m"的Base64值为38, 二进制形式是 100110.
对于文本串，编码过程如下。例如"men":
先转成US-ASCII值.
"m"十进制 109
"e"十进制 101
"n"十进制 110
二进制 :
m 01101101
e 01100101
n 01101110
三个8位连起来是24位
011011010110010101101110
然后分成4个6位
011011
010110 010101 101110
现在得到4个值，十进制为
27 22 21 46
对应的 Base64 字符是
:
b W V u
编码总是基于3个字符，从而产生4个Base64字符。
如果只剩1或2个字符，使用特殊字符"="补齐Base64的4字。
如，编码"me"
01101101 01100101
0110110101100101
011011 010110 0101
111111 (与，补足6位)
011011
010110 010100
b W U
b W U = ("=" 补足4字符)
于是 "bWU="
就是"me"的Base64值.
再如编码 "m"
01101101
011011 01
111111
011011 010000
b Q = =
于是 "bQ==" 就是"m"的Base64值.
值得注意的是，MIME规定一行最多76个字符.
*/
static String BaseTable[] = {
"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P",
"Q","R","S","T","U","V","W","X","Y","Z","a","b","c","d","e","f",
"g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v",
"w","x","y","z","0","1","2","3","4","5","6","7","8","9","+","/"
};
public static void encode(String filename, BufferedWriter out) {
try {
File f = new File(filename);
FileInputStream fin = new
FileInputStream(filename);
// 读文件到BYTE数组
byte bytes[] = new
byte[(int)(f.length())];
int n = fin.read(bytes);
if (n < 1)
return; // 没有内容
byte buf[] = new byte[4]; // base64 字符数组
int
n3byt = n / 3; // 3 bytes 组数
int nrest = n % 3; // 分组后剩余 bytes
int k =
n3byt * 3; //
int linelength = 0; // 行长
int i = 0; // 指针
//
3-bytes 分组 ...
while ( i < k ) {
buf[0] = (byte)(( bytes[i] &
0xFC) >> 2);
buf[1] = (byte)(((bytes[i] & 0x03) << 4) |
((bytes[i+1] & 0xF0) >> 4));
buf[2] = (byte)(((bytes[i+1]
& 0x0F) << 2) |
((bytes[i+2] & 0xC0) >> 6));
buf[3]
= (byte)( bytes[i+2] & 0x3F);
send(out, BaseTable[buf[0]]);
send(out, BaseTable[buf[1]]);
send(out, BaseTable[buf[2]]);
send(out, BaseTable[buf[3]]);
/*
以上代码可以优化，但会难以理解
buf[0]=
(byte)(b[i] >> 2);
buf[1]= (byte)(((b[i] & 0x03) <<
4)|(b[i+1]>> 4));
buf[2]= (byte)(((b[i+1] & 0x0F)<<
2)|(b[i+2]>> 6));
buf[3]= (byte)(b[i+2] & 0x3F);
send(out,BaseTable[buf[0]]+BaseTable[buf[1]]+
BaseTable[buf[2]]+BaseTable[buf[3]]);
*/
if ((linelength += 4)
>= 76) {
send(out, " ");
linelength = 0;
}
i += 3;
}
// 处理尾部 ...
if (nrest==2) {
// 2 bytes left
buf[0] =
(byte)(( bytes[k] & 0xFC) >> 2);
buf[1] = (byte)(((bytes[k] &
0x03) << 4) |
((bytes[k+1] & 0xF0) >> 4));
buf[2] =
(byte)(( bytes[k+1] & 0x0F) << 2);
}
else if (nrest==1) {
// 1 byte left
buf[0] = (byte)((bytes[k] & 0xFC) >> 2);
buf[1] = (byte)((bytes[k] & 0x03) << 4);
}
if (nrest >
0) {
// 发送尾部
if ((linelength += 4) >= 76) send(out, " ");
send(out, BaseTable[buf[0]]);
send(out, BaseTable[buf[1]]);
//
if (nrest==2) {
send(out, BaseTable[buf[2]]);
}
else {
send(out, "=");
}
send(out, "=");
}
out.flush();
//这里用到的send方法，请大家根据需要，自己写。可以是把结果输出到控制台，或发送邮件。
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
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