本篇内容介绍了“proc sql语句在数据清洗中的运用”的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希望大家仔细阅读，能够学有所成！
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libname clean "c:/books/clean"; /*定义永久性数据库*/
*新建一个样本数据one;
data one;
input X Y Z;
datalines;
1 2 3
101 202 303
44 55 66
444 555 666
;
title "Values of X from data set ONE where X is greater than 100";
/*有条件的选择观测值*/
proc sql;
select X
from one
where X gt 100;
quit;
*Program 8-2;
***检查无效的字符型的数值;
title "Checking for Invalid Character Data";
proc sql;
select Patno,
Gender,
DX,
AE
from clean.patients
where Gender not in ('M','F',' ') or
notdigit(trim(DX))and not missing(DX) or
AE not in ('0','1',' ');
quit;
*检查无效的数值型的数值;
title "Checking for out-of-range numeric values";
proc sql;
select Patno,
HR,
SBP,
DBP
from clean.patients
where HR not between 40 and 100 and not missing(HR) or
SBP not between 80 and 200 and not missing(SBP) or
DBP not between 60 and 120 and not missing(DBP);
quit;
*基于标准差利用简单的算法来检查数值;
title "Data values beyond two standard deviations";
proc sql;
select Patno,
SBP
from clean.patients
having SBP not between mean(SBP) - 2 * std(SBP) and
mean(SBP) + 2 * std(SBP) and
SBP is not missing;
quit;
*检查缺失值;
options linesize=84;
title "Observations with missing values";
proc sql;
select *
from clean.patients
where Patno is missing or
Gender is missing or
Visit is missing or
HR is missing or
SBP is missing or
DBP is missing or
DX is missing or
AE is missing;
quit;
*检查日期;
title "Dates before June 1, 1998 or after October 15, 1999";
proc sql;
select Patno,
Visit
from clean.patients
where Visit not between '01jun1998'd and '15oct1999'd and
Visit is not missing;
quit;
*检查重复值;
title "Duplicate Patient Numbers";
proc sql;
select Patno,
Visit
from clean.patients
group by Patno
having count(Patno) gt 1;
quit;
*识别对应多个观察值的变量;
title "Listing of patients who do not have two visits";
proc sql;
select Patno,
Visit
from clean.patients2
group by Patno
having count(Patno) ne 2;
quit;
*检查两个文件中对应要求的序列号ID;
data one;
input Patno X Y;
datalines;
1 69 79
2 56 .
3 66 99
5 98 87
12 13 14
;
data two;
input Patno Z;
datalines;
1 56
3 67
4 88
5 98
13 99
;
*两个文件都不含的ID;
title "Patient numbers not in both files";
proc sql;
select One.patno as ID_one,
Two.patno as ID_two
from one full join two
on One.patno eq Two.patno
where One.patno is missing or Two.patno is missing;
quit;
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